Poll : Hire all for 2 possibilities
Posted: Fri May 21, 2021 10:55 pm
For the time being, "engage all" engages people from the highest performers to the lowest performers in one go.
In this case, it would start by engaging the person at 85, 77 and so on.
I propose to propose the reverse. So you start at the bottom.
Like: you hire the one at 5, at 8, 20, etc.
There would then be the possibilities:
Hire the most competent
Hire the least competent
Hire an average
The average could be : If there is 11 people, hire 3
In this case, it would start by engaging the person at 85, 77 and so on.
I propose to propose the reverse. So you start at the bottom.
Like: you hire the one at 5, at 8, 20, etc.
There would then be the possibilities:
Hire the most competent
Hire the least competent
Hire an average
The average could be : If there is 11 people, hire 3
- 100
- 95
- 80
- 79
- 78
- 70
- 60
- 64
- 50
- 45
- 40
- Number 1, 2, 3
- Number 11,10,9
-
(100+95+80+79+78+70+60+64+50+45+40)/11) = 69
- 1rs : The closer that 69 = 70
- 2nd : the less competent : 60
- 3e : the more compétent : 78
- There is 11 people. 11/2 = 5,5
- 1rs and 2nd : The closer that 5,5= --->5 and 6 --> people number 5 ( 78) and 6 (70)
- 3th : 5-1 = 4 (79)
6+1 = 7